View Full Version : DateDiff function?


AnnPhil
12-16-2008, 06:47 AM
what is the correct expression for calculating the date for 3 years from todays date?

DreamGenius
12-16-2008, 06:52 AM
DateAdd("Y",3,Date)

Brianwarnock
12-16-2008, 07:01 AM
I think that should be Dateadd("yyyy",3,Date()) according to Help.

AnnPhil
12-16-2008, 07:42 AM
sorry,I need to calculate 3 years back from todays date

DreamGenius
12-16-2008, 07:43 AM
DateAdd("YYYY",-3,Date())

AnnPhil
12-16-2008, 08:45 AM
Thanks that worked great!