[
' Replace CRLF with LF only.
Me.Mailtext.Text = Replace(Me.Mailtext.Text, Chr(10) & Chr(13), Chr(10))
' If necessary replace LF with a space
Me.Mailtext.Text = Replace(Me.Mailtext.Text, Chr(10) , Chr(32))
Hi Nigel!
Replace(Me.Mailtext.Text, Chr(10) & Chr(13), Chr(32)) deletes the whole...