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In the post, I was explaining that I'm having trouble using this syntax in a Query, not in VBA

Hi. Here is an example of a function that is of a custom type: Public Type typ1 answer1 as integer answer2 as integer End Type Public Function fun1 (var1 as variant, var2 as variant) as typ1 fun1.answer1 = var1 + 1 fun1.answer2 = var2 + 2 End Function Now, in a query...