Stang70Fastback
Registered User.
- Local time
- Today, 12:06
- Joined
- Dec 24, 2012
- Messages
- 132
Here is my current setup: I have a Main Form with a tab control. On each of the six tabs is a SubForm that takes up the entire tab. So basically I have a tabbed interface for my forms, just with a bit more control over the layout than if I just opened the forms separately in the Access window.
Anyway, on one of those subforms is a button. When you click it, it opens a separate form in a pop-up window, which is used to find a specific record. Once that record is found, you can click another button, and the idea is that this pop-up window closes, and you return to the underlying form, which jumps to the record you selected.
So far so good. Now, if I am working on my program in Access, and I open that subform's source form separately in its own tab, click the icon to open the record finding form, find a record, and then click the button to load that record, the following code runs, and it runs flawlessly - closing the pop-up window, and passing the information back to the main form which displays the proper record:
Where my program falls apart is that, in actual use, this form is not open on its own. It's open as a subform on one tab of a tab control on a Main Form. So the third line of code falls apart. Access thinks I want to open CDLExam separately, but it can't because it's already open in the subform, so instead I just end up back at the main window like I want, but the form fails to move to the proper record. Basically, line 3 just doesn't do anything.
How can I make this work? I tried replacing "CDLExam" with the name of the main window, but then it tries to move to the record in the main window, which throws an error as the main window doesn't even have a record source attached to it.
I hope I was clear in what I'm trying to do. In a nutshell, I am wondering how to refer to the SUBFORM which has CDLExam open, and tell THAT to move to the proper record.
Anyway, on one of those subforms is a button. When you click it, it opens a separate form in a pop-up window, which is used to find a specific record. Once that record is found, you can click another button, and the idea is that this pop-up window closes, and you return to the underlying form, which jumps to the record you selected.
So far so good. Now, if I am working on my program in Access, and I open that subform's source form separately in its own tab, click the icon to open the record finding form, find a record, and then click the button to load that record, the following code runs, and it runs flawlessly - closing the pop-up window, and passing the information back to the main form which displays the proper record:
Private Sub ViewRecord_Click()
Dim RecordID As Integer
RecordID = Me.ID
DoCmd.OpenForm "CDLExam", , , "ID = " & RecordID
DoCmd.Close acForm, "CDLExamCONT", acSaveNo
End Sub
Where my program falls apart is that, in actual use, this form is not open on its own. It's open as a subform on one tab of a tab control on a Main Form. So the third line of code falls apart. Access thinks I want to open CDLExam separately, but it can't because it's already open in the subform, so instead I just end up back at the main window like I want, but the form fails to move to the proper record. Basically, line 3 just doesn't do anything.
How can I make this work? I tried replacing "CDLExam" with the name of the main window, but then it tries to move to the record in the main window, which throws an error as the main window doesn't even have a record source attached to it.
I hope I was clear in what I'm trying to do. In a nutshell, I am wondering how to refer to the SUBFORM which has CDLExam open, and tell THAT to move to the proper record.
Last edited: