I want to use it against a column.. not a "Hard Coded" value
"Public Function Split(ByVal InputText As String, _
Optional ByVal Delimiter As String) As Variant
' This function splits the sentence in InputText into
' words and returns a string array of the words. Each
' element of the array contains one word.
' This constant contains punctuation and characters
' that should be filtered from the input string.
Const CHARS = ".!?,;:""'()[]{}"
Dim strReplacedText As String
Dim intIndex As Integer
' Replace tab characters with space characters.
strReplacedText = Trim(Replace(InputText, _
vbTab, " "))
' Filter all specified characters from the string.
For intIndex = 1 To Len(CHARS)
strReplacedText = Trim(Replace(strReplacedText, _
Mid(CHARS, intIndex, 1), " "))
Next intIndex
' Loop until all consecutive space characters are
' replaced by a single space character.
Do While InStr(strReplacedText, " ")
strReplacedText = Replace(strReplacedText, _
" ", " ")
Loop
' Split the sentence into an array of words and return
' the array. If a delimiter is specified, use it.
'MsgBox "String:" & strReplacedText
If Len(Delimiter) = 0 Then
Split = VBA.Split(strReplacedText)
Else
Split = VBA.Split(strReplacedText, Delimiter)
End If
End Function"
This was the Split Function i have used