Getting the path to the current database
For Access 97...
'returns the database file name
Dir(CurrentDb.Name)
'returns the database path
Left(CurrentDb.Name,Len(CurrentDb.Name)-Len(Dir(CurrentDb.Name)))
'returns the database path and the file name
CurrentDb.Name
'returns the directory that Access [msaccess.exe] is installed in
(SysCmd(acSysCmdAccessDir))
For Access 2000/2002/2003...
'returns the database file name
CurrentProject.Name
'returns the database path
CurrentProject.Path
'returns the database path and the file name
CurrentProject.FullName
HTH