Creating a 'back' action button

Nathc917

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Aug 3, 2015
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Hi,

I'm relatively new to access access web apps. I'm trying to create a 'back' button for some of my forms. I've got multiple forms for the same table and want a 'back' button available for when users navigate away from the main form. Basically it just needs to switch view but remain within the same record.

I'm using the following afterclick action on a button for users to navigate from the main form to other forms which is working.

Table ConditionAuditcomments
View _VI2
Where [ConditionAuditcomments.ID]=[IDTextBox]

I'm using the where condition to keep users within the same record.
I tried to create a 'back' button for users to go back to the main form using the same 'where' condition but get the error 'invalid field name, ConditionAuditcomments'

Table ConditionAuditcomments
View ConditionAuditcommentslist
Where [ConditionAuditcomments.ID]=[IDTextBox]

I've tried a few other things but can't get the where condition to work. If I remove it I can navigate back to the main form but it doesn't stay within the record.

Any help would be greatly appreciated, thanks!
Nathan.
 
Does:

Table ConditionAuditcomments
View ConditionAuditcommentslist
Where [ConditionAuditcomments].[ID]=[IDTextBox]

fix it by any chance? assuming that ID is the ID field in the ConditionAuditcomments table?
 

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