This function will work in Access 97:
Function Median(tName$, fldName$) As Single
Dim MedianDB As Database
Dim ssMedian As Recordset
Dim RCount%, i%, x%, y%, OffSet%
Set MedianDB = CurrentDb()
Set ssMedian = MedianDB.OpenRecordset("SELECT [" & fldName$ & "] FROM [" & tName$ & _
"] WHERE [" & fldName$ & "] IS NOT NULL ORDER BY [" & fldName$ & "];")
'NOTE: To include nulls when calculating the median value, omit
'WHERE [" & fldName$ & "] IS NOT NULL from the example.
ssMedian.MoveLast
RCount% = ssMedian.RecordCount
x% = RCount% Mod 2
If x% <> 0 Then
OffSet% = ((RCount% + 1) / 2) - 2
For i% = 0 To OffSet%
ssMedian.MovePrevious
Next i
Median = ssMedian(fldName$)
Else
OffSet% = (RCount% / 2) - 2
For i% = 0 To OffSet%
ssMedian.MovePrevious
Next i
x% = ssMedian(fldName$)
ssMedian.MovePrevious
y% = ssMedian(fldName$)
Median = (x% + y%) / 2
End If
ssMedian.Close
MedianDB.Close
End Function
HTH
RDH
[This message has been edited by R. Hicks (edited 10-06-2001).]