Gasman
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Hi all,
I am using a routine that populates my combobox if the value is not there using the NotInList event. The data is entered in the form Surname Initial.Initial
The relevant code is hown below.
However as it is now, I have to remove the initials from the opened form that displays the new value added each time
So I tried the line
NewData = Left(NewData, InStr(NewData, " ") - 1)
to give me just the surname, but whilst that passes the correct value on, I get a repeat of the Not in list message and then property not found message when I return to the data entry form and the fieldis not populated as it is with the correct value when I do not use this line of code. Nor are any options showing in the drop down until I backspace sufficient to see and select the new value.
I made this amendment to speed up data entry, but it is having the opposite effect at present, hence commenting that line out.
I cannot find out why this behaviour is occurring and hoping for some expert help?
TIA
I am using a routine that populates my combobox if the value is not there using the NotInList event. The data is entered in the form Surname Initial.Initial
The relevant code is hown below.
However as it is now, I have to remove the initials from the opened form that displays the new value added each time
So I tried the line
NewData = Left(NewData, InStr(NewData, " ") - 1)
to give me just the surname, but whilst that passes the correct value on, I get a repeat of the Not in list message and then property not found message when I return to the data entry form and the fieldis not populated as it is with the correct value when I do not use this line of code. Nor are any options showing in the drop down until I backspace sufficient to see and select the new value.
I made this amendment to speed up data entry, but it is having the opposite effect at present, hence commenting that line out.
I cannot find out why this behaviour is occurring and hoping for some expert help?
TIA
Code:
Private Sub Crew_ID_NotInList(NewData As String, Response As Integer)
'Dim strSurname As String
'NewData = Left(NewData, InStr(NewData, " ") - 1)
Response = AddNewToList(mixed_case(NewData), "Crew", "Surname", "Crews", "frmCrew")
End Sub
'************** Code Start *************
'This code was originally written by Jay Holovacs.
'It is not to be altered or distributed,
'except as part of an application.
'You are free to use it in any application,
'provided the copyright notice is left unchanged.
'
'Code Courtesy of
'Jay Holovacs
'
Public Function mixed_case(str As Variant) As String
'returns modified string, first character of each word us uppercase
'all others lower case
Dim ts As String, ps As Integer, char2 As String
If IsNull(str) Then
mixed_case = ""
Exit Function
End If
str = Trim(str) 'added 11/22/98
If Len(str) = 0 Then
mixed_case = ""
Exit Function
End If
ts = LCase$(str)
ps = 1
ps = first_letter(ts, ps)
Special_Name ts, 1 'try to fix the beginning
Mid$(ts, 1) = UCase$(Left$(ts, 1))
If ps = 0 Then
mixed_case = ts
Exit Function
End If
While ps <> 0
If is_roman(ts, ps) = 0 Then 'not roman, apply the other rules
Special_Name ts, ps
Mid$(ts, ps) = UCase$(Mid$(ts, ps, 1)) 'capitalize the first letter
End If
ps = first_letter(ts, ps)
Wend
mixed_case = ts
End Function
Private Sub Special_Name(str As String, ps As Integer)
'expects str to be a lower case string, ps to be the
'start of name to check, returns str modified in place
'modifies the internal character (not the initial)
Dim char2 As String
char2 = Mid$(str, ps, 2) 'check for Scots Mc
If (char2 = "mc") And Len(str) > ps + 1 Then '3rd char is CAP
Mid$(str, ps + 2) = UCase$(Mid$(str, ps + 2, 1))
End If
char2 = Mid$(str, ps, 2) 'check for ff
If (char2 = "ff") And Len(str) > ps + 1 Then 'ff form
Mid$(str, ps, 2) = LCase$(Mid$(str, ps, 2))
End If
char2 = Mid$(str, ps + 1, 1) 'check for apostrophe as 2nd char
If (char2 = "'") Then '3rd char is CAP
Mid$(str, ps + 2) = UCase$(Mid$(str, ps + 2, 1))
End If
Dim char3 As String
char3 = Mid$(str, ps, 3) 'check for scots Mac
If (char3 = "mac") And Len(str) > ps + 1 Then 'Mac form
Mid$(str, ps + 3) = UCase$(Mid$(str, ps + 3, 1))
End If
Dim char4 As String
char4 = Mid$(str, ps, 4) 'check for Fitz
If (char4 = "fitz") And Len(str) > ps + 1 Then 'Fitz form
Mid$(str, ps + 4) = UCase$(Mid$(str, ps + 4, 1))
End If
End Sub
Private Function first_letter(str As String, ps As Integer) As Integer
'ps=starting point to search (starts with character AFTER ps)
'returns next first letter, 0 if no more left
'modified 6/18/99 to handle hyphenated names
Dim p2 As Integer, p3 As Integer, s2 As String
s2 = str
p2 = InStr(ps, str, " ") 'points to next blank, 0 if no more
p3 = InStr(ps, str, "-") 'points to next hyphen, 0 if no more
If p3 <> 0 Then
If p2 = 0 Then
p2 = p3
ElseIf p3 < p2 Then
p2 = p3
End If
End If
If p2 = 0 Then
first_letter = 0
Exit Function
End If
'first move to first non blank, non punctuation after blank
While is_alpha(Mid$(str, p2)) = False
p2 = p2 + 1
If p2 > Len(str) Then 'we ran off the end
first_letter = 0
Exit Function
End If
Wend
first_letter = p2
End Function
Public Function is_alpha(ch As String)
'returns true if this is alphabetic character
'false if not
Dim c As Integer
c = Asc(ch)
Select Case c
Case 65 To 90
is_alpha = True
Case 97 To 122
is_alpha = True
Case Else
is_alpha = False
End Select
End Function
Private Function is_roman(str As String, ps As Integer) As Integer
'starts at position ps, until end of word. If it appears to be
'a roman numeral, than the entire word is capped in passed back
'string, else no changes made in string
'returns 1 if changes were made, 0 if no change
Dim mx As Integer, p2 As Integer, flag As Integer, i As Integer
mx = Len(str) 'just so we don't go off the edge
p2 = InStr(ps, str, " ") 'see if there is another space after this word
If p2 = 0 Then
p2 = mx + 1
End If
'scan to see if any inappropriate characters in this word
flag = 0
For i = ps To p2 - 1
If InStr("ivxIVX", Mid$(str, i, 1)) = 0 Then
flag = 1
End If
Next i
If flag Then
is_roman = 0
Exit Function 'this is not roman numeral
End If
Mid$(str, ps) = UCase$(Mid$(str, ps, p2 - ps))
is_roman = 1
End Function
'************** Code End *************
' usage..... Response = AddNewToList(NewData, "LtblCounties", "txtCounty", "Counties")
Public Function AddNewToList(NewData As String, stTable As String, _
stFieldName As String, strPlural As String, _
Optional strNewForm As String) As Integer
On Error GoTo err_proc
'Adds a new record to a drop down box list
'If form name passed, then open this form to the newly created record
'Declare variables
Dim rst As DAO.Recordset
Dim IntNewID As Long
Dim strPKField As String
Dim strMessage As String
' Display message box asking if user wants to add the new item
strMessage = "'" & NewData & "' is not in the current list. " & Chr(13) & Chr(13) & _
"Do you want to add it to the list of " & strPlural & "?" & Chr(13) & Chr(13) & _
"(Please check the entry before proceeding)."
If MsgBox(strMessage, vbYesNo + vbQuestion + vbDefaultButton2, "Add New Data") = vbYes Then
Set rst = CurrentDb.OpenRecordset(stTable, , dbAppendOnly)
rst.AddNew
rst(stFieldName) = NewData 'Add new data from combo box
strPKField = rst(0).Name 'Find name of Primary Key (ID) Field
rst.Update
rst.Move 0, rst.LastModified
IntNewID = rst(strPKField)
'if a form specified, then open the form with the primary key equal to the new record ID as the criteria
If strNewForm <> "" Then DoCmd.OpenForm strNewForm, , , strPKField & "=" & IntNewID
AddNewToList = acDataErrAdded 'Set response 'Data added'
Else
AddNewToList = acDataErrContinue 'Set response 'Data NOT added'
End If
exit_proc:
On Error Resume Next
rst.Close
Set rst = Nothing
Exit Function
err_proc:
MsgBox "Error in Function: 'AddNewToList'" & Chr(13) & Err.Description, , "Function Error"
Resume exit_proc
End Function
'Notes:
'1. The Primary Key field must be numeric (long integer) and must always be the first field in the table.
'2. The 'Limit to List' property of the combo box must be set to 'Yes'
'3. strNewForm is opened in edit mode as the new record is added first and the form then opened to that record. A consequence of this is that other fields in the table must have their 'Required' property set to 'No' or a (valid) default property value set in the table design.
'4. FieldNamePlural is there simply to make the message grammatically correct; in the AddNewToList code the message box string generated as: strMessage = "'" & NewData & "' is not in the current list. " & Chr(13) ..... would result in the warning message (e.g.):
'London' is not in the current list. "
'Do you want to add it to the list of Cities?
'(Please check the entry before proceeding).
'5. If an edit form is opened (strNewForm <> "") then the field that is displayed in the combo box should be in a locked control on the form, alternatively remove the acDialog argument and ensure the combo box is re-queried when the form is closed.
'6. The form 'strNewForm' should have it's 'Allow Additions' and 'Data Entry' properties set to 'No' to prevent users from adding additional entries to the entry requested by the Not In List event.
'Enjoy!
'Edit1: 18/02/2013: Added Note 4
'Edit2: 02/03/2014: Added Notes 5 & 6.