Solved Pages count is 0 (1 Viewer)

[Kayleigh]

Hi

I am attempting to set some objects in page footer to only appear on last page in report. So I tried to use methods shown here or here

My issue is that the Pages property always returns 0 so it can't calculate last page in report. I am not sure if this is due to it being opened on a filter. (Which I could resolve by always changing recordsource on load.

Can anyone help me figure this out please.

Thanks for your continuous support
Kayleigh

 

[theDBguy]

Are you already displaying the page numbers on your report? If so, what is the expression you're using?

 

[Kayleigh]

No. I've just been using Me.pages in vba for the logic

 

[The_Doc_Man]

You should be able to put a text box in the appropriate page footer or report footer and use the "expression builder" to define what you want printed there. Since there is a drop down list of choices, you will be sure to get the right one.

 

[theDBguy]

No. I've just been using Me.pages in vba for the logic

VBA may not be good enough. Try adding a hidden textbox for the pages to see if it makes a difference.

 

[Pat Hartman]

You need to have page x of y in the header/foote so that both page and pages are defined in the header/footer. The no-code solution might be to create a subreport that appears only in the Report Footer section.

Just FYI having page x of y greatly decreases the speed of producing the report since Access has to paginate the ENTIRE report in memory BEFORE it can render the first page in order to show the y value for pages.

 

[Kayleigh]

Thank you. I will try that

I'm not concerned about the speed as these reports will only be couple pages at most (or just one page usually).

 

[Pat Hartman]

Let us know which method you decided on.

 

[Kayleigh]

Hi

Best method which worked for me was having textbox 'page n of m' in page footer. Then use following VBA for logic:

Private Sub PageFooterSection_Format(Cancel As Integer, FormatCount As Integer)
If Page = Pages Then
   Me.Image53.Visible = True
Else
   Me.Image53.Visible = False
End If
End Sub

Thanks for all the suggestions