Brain Teasers

[Pauldohert]

1 part strawberry - 99 parts water = 99% water.
1 part strawberry (the strawberry doesnt diminish) and 49 parts water (the water diminishes) = 98% water.

So the weight is now 50 was 100.

 

[Access_guy49]

1 part strawberry - 99 parts water = 99% water.
1 part strawberry (the strawberry doesnt diminish) and 49 parts water (the water diminishes) = 98% water.

So the weight is now 50 was 100.

i c.... interesting. lol.
Thanks.

 

[dan-cat]

You do know more about door 2 after the reveal , cos door 2 was part of the group that was 2/3 chance of being right. But you know the rest of that set ie door 3 is definatley wrong. So the 2/3 chance is all concentrated in door 2.

Where has this group of '2/3 chance of being right' come from and why isn't door1 a part of it? Before the reveal each door stands on its own. That is from where your 33% for each door derives.

An opinion on the state of a particular door is completely arbitary when defining the probability of its true state.

In no way throughout the entire process is the state of door1 and door2 different. Yet door2 is allowed a 33.33% increase in probability whereas door1 is not.

Door 2 was part of the group that was 2/3 chance of being right whereas Door 1 was not? How, when and where?

 

[ChipperT]

My mistake was day 2 he doesn't make a profit! Isn't it? Arggh!

Keep them coming.

No, he broke even on day 1, he made $100.00 on day 2 so the total profit was $100.00.

 

[Pauldohert]

No, he broke even on day 1, he made $100.00 on day 2 so the total profit was $100.00.

Yep - we are agreeing I think. In isolation day 1 was profitable based on what he paid for what he sold that day and the difference between.

Day two - he made nothing cos although it was 2 times the price it had diminished over night to half the weight.
So in isolation day two he made no profit.

 

[Access_guy49]

Where has this group of '2/3 chance of being right' come from and why isn't door1 a part of it? Before the reveal each door stands on its own. That is from where your 33% for each door derives.

An opinion on the state of a particular door is completely arbitary when defining the probability of its true state.

In no way throughout the entire process is the state of door1 and door2 different. Yet door2 is allowed a 33.33% increase in probability whereas door1 is not.

Door 2 was part of the group that was 2/3 chance of being right whereas Door 1 was not? How, when and where?

Perhaps it would help people to think of it another way.... the opposite way.
When you have the option of all 3 doors, only one door is a winner. That we know. So you have a 66% chance of picking the wrong door.
So by that, you always have higher odds of being wrong. If given the option to switch doors, you should take it (according to the fact that you had a 66% chance being wrong on your first guess) and since you only get to choose one door because the host revealed the other one, then you increase your odds to make that OTHER door 66% chance of being the winning door.

 

[ChipperT]

Perhaps it would help people to think of it another way.... the opposite way.
When you have the option of all 3 doors, only one door is a winner. That we know. So you have a 66% chance of picking the wrong door.
So by that, you always have higher odds of being wrong. If given the option to switch doors, you should take it (according to the fact that you had a 66% chance being wrong on your first guess) and since you only get to choose one door because the host revealed the other one, then you increase your odds to make that OTHER door 66% chance of being the winning door.

Well, THAT sure cleared it up... NOT!

 

[ChipperT]

Here is a simple one. How many errors are in the following?

"Their are four misteaks in this sentence"

 

[Kryst51]

Here is a simple one. How many errors are in the following?

"Their are four misteaks in this sentence"

Is it just me or is this meant to trip us up? There are only 4 errors if you count the fact that there are only 3 errors, thus making the count of "four" an error intelf bringing the total to 4 errors, thus negating the falsehood of it, and reducing the count to three.... and round and round it goes.... Or am I completely off base?

 

[ChipperT]

Is it just me or is this meant to trip us up? There are only 4 errors if you count the fact that there are only 3 errors, thus making the count of "four" an error intelf bringing the total to 4 errors, thus negating the falsehood of it, and reducing the count to three.... and round and round it goes.... Or am I completely off base?

I like the way you think. It is wrong, but I like the way you think.

 

[chergh]

Here is a simple one. How many errors are in the following?

"Their are four misteaks in this sentence"

None, all the errors were intentional and therefore aren't really errors.

 

[Kryst51]

I like the way you think. It is wrong, but I like the way you think.

I thought of my answer on my own, but with your response googled it and came up with This

This confirms my suspicions, but given the comments by others there is debate..... So in one way I am right, it just depends on how you interpret it.

 

[Kryst51]

I also like the reasoning behind Chergh's answer.... I wish I had thought of it first.

 

[ChipperT]

I thought of my answer on my own, but with your response googled it and came up with This

This confirms my suspicions, but given the comments by others there is debate..... So in one way I am right, it just depends on how you interpret it.

Actually This is wrong, but I would not say that emphatically or empirically.

 

[pbaldy]

I was going to say:

3: misuse of "their", spelling error on "mistakes", and no period at the end

I disagree with that site; it doesn't seem like you should count the same word as both a spelling and grammatical problem. It's one or the other.

 

[ChipperT]

None, all the errors were intentional and therefore aren't really errors.

Good try and could possibly be correct in an alternate universe other than the one I exist in.

 

[ChipperT]

I was going to say:

3: misuse of "their", spelling error on "mistakes", and no period at the end

I disagree with that site; it doesn't seem like you should count the same word as both a spelling and grammatical problem. It's one or the other.

pbaldy, you pointed out an error that I had inadvertantly introduced - that of the missing punctuation. Therefore I must eat crow. Kryst51 is correct and I must humbly beg her forgiveness.

 

[chergh]

pbaldy, you pointed out an error that I had inadvertantly introduced - that of the missing punctuation. Therefore I must eat crow. Kryst51 is correct and I must humbly beg her forgiveness.

Can I change my answer to 1

 

[Kryst51]

pbaldy, you pointed out an error that I had inadvertantly introduced - that of the missing punctuation. Therefore I must eat crow. Kryst51 is correct and I must humbly beg her forgiveness.

Consider yourself forgiven <said haughtily and regally, and if I had a sceptor I might just use it to tap your shoulders in a pardoning gesture. >

 

[pbaldy]

Okay, here's one I remembered from my youth. It's a visual, attached (forgive my non-existent art skills). The lines represent 4 toothpicks, arranged in the shape of a martini glass. The circle is an olive. You are to move two of the toothpicks in such a way as to redraw the glass but leaving the olive outside the glass.