Hi,
I am using the DateDiff function and getting #error when the 2nd date is 31/12/9999 (I know this is the problem but that is how my source data is presented to me).
What I'd like to do is replace the #error with 0.
The formula I have is:
Months: DateDiff("m",[Installation Start Date],[Installation End date]+1)
Any advice much appreciated.
I am using the DateDiff function and getting #error when the 2nd date is 31/12/9999 (I know this is the problem but that is how my source data is presented to me).
What I'd like to do is replace the #error with 0.
The formula I have is:
Months: DateDiff("m",[Installation Start Date],[Installation End date]+1)
Any advice much appreciated.