group values in a query

[ryprobg]

hello need a quick help to grouping (service maintenancier) in this query by geting (somme of NB service) once time this is the maximun value of dcount for (service maintenancier)..
the meaning is to groupnig each (service maintenancier) with there (somme of nb TR)
exemple :
Atelier Bulls et camions : 3
Atelier Electrique Engins : 2
Atelier Electrique Engins : 1
Station service : 1
please refere to the attachements below

 

[arnelgp]

create Total query from your query.

 

[plog]

Please use data to demonstrate what you want. Provide 2 sets of data:

A. Starting data from your tables. Include table/field names and enough data to cover all cases.

B. Expected results of A. Show us what data you expect your query to generate when you feed it the data from A.

Again, 2 sets of data--started and expected results based on the starting data.

 

[arnelgp]

select [service maintenance:], count("1") As CountOfMaintenance from [test unique]
group by [service mintenance:]

 

[ryprobg]

select [service maintenance:], count("1") As CountOfMaintenance from [test unique]
group by [service mintenance:]

how i can make the somme of count (CompteDeNR) by service maintenance and by date and SommeDeTR like this :
* atelier Bull et camions : 20/09/2022 | ( 1+1+1) | (4.19 +3+5.3)
* atelier Electrique Engins : 20/09/2022 | ( 1+1) | (5.19 +2)
* station service : 20/09/2022 | (1) | (0)
* atelier Bull et camions : 21/09/2022 | ( 1+1) | (2.09+0)

 

[ryprobg]

how i can make the somme of count (CompteDeNR) by service maintenance and by date and SommeDeTR like this :
* atelier Bull et camions : 20/09/2022 | ( 1+1+1) | (4.19 +3+5.3)
* atelier Electrique Engins : 20/09/2022 | ( 1+1) | (5.19 +2)
* station service : 20/09/2022 | (1) | (0)
* atelier Bull et camions : 21/09/2022 | ( 1+1) | (2.09+0)

anyone help please!!!!!!!!!!!!!

 

[Gasman]

Little impatient aren't we?

You group by all the required fields?

 

[arnelgp]

you create a Total query from your original query/table.
see Query1 on this demo.