Chocolate Math!!!

[skea]

Reason out the logic behind this chocolate Math!!!
It tells your Age.

1) Pick the number of times you would like to have chocolate in a week(It should be more than 1 and less than 10).
2) Multiply the number by 2(Just to be bold)
3) Add 5 to it.
4) Multiply the result by 50 (I will wait... as you launch that calculator)
6) If you have already had your bithday this year, Add 1755 and if not Add 1754.
7) Now subtract the 4 digit year that you were born.
.....You should be having a three digit number.
The first digit was your orignal number(how many times you would like chocolate in a week.)
The Next Two Numbers are Your AGE!!!(Oh YES, It is!!!)

Now Reason out.

 

[Andromeda]

yeah nice mathematical equations!thanks that's cool...

it's all about math! and it's fun doing it!

 

[skea]

Probably the best way to see why this works is to avoid committing to
a specific number and see what happens. Instead of picking a number,
I'm going to use 'n' to represent some choice I haven't yet made.

Let's see what happens as I follow the steps:

1) n

2) 2n

3) 2n + 5

4) 100n + 250

5) 100n + (2001 or 2002)

6) 100n + (2001 or 2002) - (year of birth)

Now, let's look at what I ended up with. If we write it this way,

100n + (2001 or 2002) - (year of birth)

= 100n + [(year of my last birthday) - (year of my birth)]

= 100n + [my age]

This might be a good time to note that if you start with a number
greater than 9, or if you're more than 99 years old, the trick won't
work.

So basically, the trick is saying that

50(2n + 5) + 1750 + i - (year of birth)

where i (for 'increment') is the number of years past 2000 for the
year when you had your last birthday, equal to

100n + (your age)

which is, of course, true (for 0 < n < 10, and age < 100):

50(2n + 5) + 1750 + i - (yob)

= (100n + 250) + 1750 + i - (yob)

= 100n + (250 + 1750 + i) - yob

= 100n + (2000 + i) - (yob)

= 100n + (your age)

It _is_ true that with these specific numbers, the trick will work
only this year. However, if you want it to work next year, you can
just change i to '2 or 3' instead of '1 or 2'.

Some other variations on the problem would be

25(4n + 10) + 1750 + i - (year of birth)

20(5n + 10) + 1800 + i - (year of birth)

4(25n + 127) + 1492 + i - (year of birth)

4(25n + 224) + 1776 + i - (year of birth)

In general, you have

a(bn + c) + d + i - (year of birth)

and the constraints you have to meet are

1) ab = 100

2) ac + d = 2000

Let's say I want to make d = 1908, the last year the Chicago Cubs won
the World Series. Then

ac + 1908 = 2000

ac = 2000 - 1908

ac = 92

= 2 * 2 * 23

The possible values of a and c are:

a = 1, c = 92
a = 2, c = 46
a = 4, c = 23
a = 23, c = 4
a = 96, c = 1

But 2 and 4 are the only values of a that divide 100 evenly, so I can
have either

2(50n + 46) + 1908 + i - (year of birth)

or

4(25n + 23) + 1908 + i - (year of birth)

Got it from here

 

[Isaac]

First, I've always wanted to reply to an old thread since I know that makes people's head melt (for some reason).
Second, this did not work out for me. Or else I'm really 25, was raised by wolves, then created a bunch of false memories to (for some reason) believe I was over 40. This exercise consistently (at least), tells me I'm 25 ... So I'm now seriously questioning my history and identity. And not to be trendy, either!

Whaaaaat?

 

[Uncle Gizmo]

this did not work out for me

Is your math ability in question?

I haven't tried it myself btw ...

 

[Isaac]

I promise I used the calculator all the way, except for the first 2 - and even for those after I began to doubt my sanity

 

[The_Doc_Man]

My problem, that makes me not even bother, is that the limit on the number of times per week I want chocolate, is not less than 10.

 

[Isaac]

Oh c'mon, two people responded so far and neither has tried it. Now this is going to drive me nuts.
I'm odd, chocolate doesn't appeal to me that much, but I have my weaknesses ... for ice cream it would be the caramel types, or anything with large chunks of non-ice cream in it (weird, since I'm paying for ice cream).

 

[pbaldy]

I've always wanted to reply to an old thread since I know that makes people's head melt

Oh my God, I don't think I can take this!!

It goofed mine too, I'm only 49 according to this. Sadly, that's way in the past for me.

 

[pbaldy]

chocolate doesn't appeal to me that much, but I have my weaknesses ... for ice cream it would be the caramel types

I'm a chocoholic, but my wife would fight you over the caramel.

 

[NauticalGent]

Not even close for me. My final number was 50. The first number was correct but I am quite sure I am more than zero years old...

 

[kevlray]

Did not work for me. Got the number of chocolates right but reduced my age by 16 years.

 

[NauticalGent]

reduced my age by 16 years.

if only

 

[Isaac]

So my mind immediately goes to, why did it appear to work for 2 people, in 2005?
Fortunately this didn't keep me up last night (although I had some weird dreams, they weren't about math).

Oh, well. Someday someone will post an explanation - or we'll just have to conclude that the original 2 people were only pretending.
How positively odd.
Thanks 4 trying folks

 

[Cronk]

It works if the year is 2005. 16 years later in 2021, substitute 1771 and 1770.

When you add 250 (which is the original 5 multiplied by 250) and add the 4 digit number you get 2021 and subtracting your birth year gives the age - hopefully less than 100

Twice the number of chocolates times 50 is 100 times ie the leading figure in front of the result.

 

[Isaac]

Oh.............of course, it was numbers specific to that year. You're a genius, sir, and thank you for posting that.
See - I knew someone with algebra knowledge would figure out what was going on here.

Thanks, @Cronk , I really wanted to send this to my Dad, and now I can.

 

[NauticalGent]

t works if the year is 2005. 16 years later in 2021, substitute 1771 and 1770.

I am almost impressed...