Hi
I hope someone can help with this as I can't seem to get this query to work.
I am trying to use a query to search for the highest value in a column but based upon a specific criteria.
i.e. in the column will be ABC1234, ABC1235, ABC1236 and BBC1234 and I want to get the highes 'ABC' value
I looked on the forum and found this code
Dim strSQL As String
Dim MyValue As DataType 'Replace the proper datatype of field
Dim rs As ADODB.Recordset, Cn As ADODB.Connection
Set rs = New ADODB.Recordset
Set Cn = New ADODB.Connection
Set Cn = CurrentProject.Connection
strSQL = "SELECT tableName.ColumnName FROM tableName ORDER BY tableName.ColumnName DESC"
rs.Open strSQL, Cn, adOpenStatic, adLockReadOnly
MyValue = rs!ColumnName
rs.Close
Set rs = Nothing
I've modified the query to this
strSQL = "SELECT tableName.ColumnName FROM tableName WHERE tableName.ColumnName Like 'ABC*' ORDER BY tableName.ColumnName DESC"
This doesn't bring anything back but I was expecting 'ABC1236'
I'm new to using 'Like' so this could be the problem.
Your help is much appreciated.
I hope someone can help with this as I can't seem to get this query to work.
I am trying to use a query to search for the highest value in a column but based upon a specific criteria.
i.e. in the column will be ABC1234, ABC1235, ABC1236 and BBC1234 and I want to get the highes 'ABC' value
I looked on the forum and found this code
Dim strSQL As String
Dim MyValue As DataType 'Replace the proper datatype of field
Dim rs As ADODB.Recordset, Cn As ADODB.Connection
Set rs = New ADODB.Recordset
Set Cn = New ADODB.Connection
Set Cn = CurrentProject.Connection
strSQL = "SELECT tableName.ColumnName FROM tableName ORDER BY tableName.ColumnName DESC"
rs.Open strSQL, Cn, adOpenStatic, adLockReadOnly
MyValue = rs!ColumnName
rs.Close
Set rs = Nothing
I've modified the query to this
strSQL = "SELECT tableName.ColumnName FROM tableName WHERE tableName.ColumnName Like 'ABC*' ORDER BY tableName.ColumnName DESC"
This doesn't bring anything back but I was expecting 'ABC1236'
I'm new to using 'Like' so this could be the problem.
Your help is much appreciated.