scubadiver007
Registered User.
- Local time
- Today, 09:36
- Joined
- Nov 30, 2010
- Messages
- 317
I have a drop-down box on a form to select a K-Code.
I can open query5 using the drop-down no problem but trying to export the data from Query5 to an Excel sheet comes up with this error. So I don't know where the problem lies.
I have three tables
ES Database figures:
ID
Service
Indicator
Practice_Code
Q1
Q2
Q3
Q4
Service list:
ID
Service
Indicator
Signup:
K-Code
Service
ID
Signup
Five Queries -
Query1:
SELECT [Service list].ID, [Service list].Service, [Service list].Indicator
FROM [Service list];
Query2:
SELECT [ES Database figures].ID, [ES Database figures].Service, [ES Database figures].Indicator, [ES Database figures].Practice_Code, [ES Database figures].Q1, [ES Database figures].Q2, [ES Database figures].Q3, [ES Database figures].Q4
FROM [ES Database figures]
WHERE ((([ES Database figures].Practice_Code)=[forms]![form1]![Practice_List]));
Query3 links Query1 and Query2 using an outerjoin because I need to select every service and indicator regardless of whatever data is available from the "ES database figures".
SELECT Query1.ID, Query1.Service, Query1.Indicator, Query2.Practice_Code, Query2.Q1, Query2.Q2, Query2.Q3, Query2.Q4
FROM Query1 LEFT JOIN Query2 ON Query1.ID = Query2.ID;
Query4 selects the K-Code so the correct sign up information is used.
SELECT Signup.[K-code], Signup.Service, Signup.ID, Signup.Signup
FROM Signup
WHERE (((Signup.[K-code])=[forms]![form1]![Practice_List]));
Query5 links Query3 and Query4 using an outer join.
SELECT Query4.Signup, Query3.Q1, Query3.Q2, Query3.Q3, Query3.Q4
FROM Query4 RIGHT JOIN Query3 ON Query4.ID = Query3.ID;
I can provide a basic example if it will help.
I can open query5 using the drop-down no problem but trying to export the data from Query5 to an Excel sheet comes up with this error. So I don't know where the problem lies.
I have three tables
ES Database figures:
ID
Service
Indicator
Practice_Code
Q1
Q2
Q3
Q4
Service list:
ID
Service
Indicator
Signup:
K-Code
Service
ID
Signup
Five Queries -
Query1:
SELECT [Service list].ID, [Service list].Service, [Service list].Indicator
FROM [Service list];
Query2:
SELECT [ES Database figures].ID, [ES Database figures].Service, [ES Database figures].Indicator, [ES Database figures].Practice_Code, [ES Database figures].Q1, [ES Database figures].Q2, [ES Database figures].Q3, [ES Database figures].Q4
FROM [ES Database figures]
WHERE ((([ES Database figures].Practice_Code)=[forms]![form1]![Practice_List]));
Query3 links Query1 and Query2 using an outerjoin because I need to select every service and indicator regardless of whatever data is available from the "ES database figures".
SELECT Query1.ID, Query1.Service, Query1.Indicator, Query2.Practice_Code, Query2.Q1, Query2.Q2, Query2.Q3, Query2.Q4
FROM Query1 LEFT JOIN Query2 ON Query1.ID = Query2.ID;
Query4 selects the K-Code so the correct sign up information is used.
SELECT Signup.[K-code], Signup.Service, Signup.ID, Signup.Signup
FROM Signup
WHERE (((Signup.[K-code])=[forms]![form1]![Practice_List]));
Query5 links Query3 and Query4 using an outer join.
SELECT Query4.Signup, Query3.Q1, Query3.Q2, Query3.Q3, Query3.Q4
FROM Query4 RIGHT JOIN Query3 ON Query4.ID = Query3.ID;
I can provide a basic example if it will help.